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f(x)=(1-tanx)[1+√2sin(2x+π\/4)]=(1-tanx)[1+√2(sin2x*cosπ\/4+sinπ\/4*cos2x)]=(1-tanx)[1+√2(√2\/2sin2x+√2\/2cos2x)]=(1-tanx)(1+sin2x+cos2x)=(1-tanx)(1+2sinx*cosx+cos2x-sin2x)=(1-tanx)[1+(2sinx*cosx+cos2x-sin2x)\/1]=(1-tanx)[1+(2sinx*cosx+cos2x-sin2x)\/(cos2x+sin2x)]=(1-tanx)[1+(2sinx\/cosx+1-sin2x\/co...